The maximum current that each output can handle is 500mA. However, it's recommended to derate the current to 350mA for reliable operation.
The power dissipation of the ULN2804A can be calculated using the formula: Pd = (Vin - Vout) x Iout x N, where Vin is the input voltage, Vout is the output voltage, Iout is the output current, and N is the number of outputs.
The minimum input voltage required for the ULN2804A to function properly is 4.5V. However, it's recommended to use a minimum of 5V for reliable operation.
Yes, the ULN2804A can be used as a relay driver. However, it's essential to ensure that the relay coil current is within the maximum current rating of the ULN2804A (500mA per output).
To protect the ULN2804A from back-EMF when driving inductive loads, a freewheeling diode (such as 1N4007) should be connected in parallel with the load. This diode will absorb the back-EMF and prevent damage to the ULN2804A.