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-556C Datasheet

Part Manufacturer Description PDF Type
556C1 Test Products International Equipment - Environmental Testers, Test and Measurement, DGTL AIR VELOCITY/AIR FLOW METER Original

-556C

Catalog Datasheet MFG & Type PDF Document Tags
Abstract: : Winding power loss = (IL12 + IL22 ) × DCR in Watts (W) 55.6°C Temperature rise (t) = Winding power loss × W 55.6°C t = (IL12 + IL22 ) × DCR × W Example 1. MSD1260T-153ML (Equal current in each winding) Winding power loss = (2.06 2 + 2.06 2) × 0.085 = 0.721 W 55.6°C = 40°C t = 0.721 W × W Example 2. MSD1260T-153ML (IL1 = 2.4 A, IL2 = 1.3 A) Winding power loss = (2.4 2 + 1.3 2) × 0.085 = 0.633 W t = 0.633 W × 55.6°C Coilcraft
Original
MSD1260T
Abstract: power loss = (IL12 + IL22 ) × DCR in Watts (W) 55.6°C Temperature rise (t) = Winding power loss × W 55.6°C t = (IL12 + IL22 ) × DCR × W Example 1. MSD1260T-153ML (Equal current in each winding) Winding power loss = (2.06 2 + 2.06 2) × 0.085 = 0.721 W 55.6°C = 40°C t = 0.721 W × W Example 2 , 0.633 W × 55.6°C = 35.2°C W Coupled Inductor Core and Winding Loss Calculator This web-based Coilcraft
Original
MSD1260T-224KL 556C SR-332
Abstract: Winding power loss = (IL12 + IL22 ) × DCR in Watts (W) 55.6°C Temperature rise ( t) = Winding power loss × W 55.6°C t = (IL12 + IL22 ) × DCR × W Example 1. 590PND153 (Equal current in each winding) Winding power loss = (2.06 2 + 2.06 2) × 0.085 = 0.721 W 55.6°C t = 0.721 W × = 40°C W Example 2. 590PND153 (I L1 = 2.4 A, IL2 = 1.3 A) Winding power loss = (2.4 2 + 1.3 2) × 0.085 = 0.633 W t = 0.633 W × 55.6°C Coilcraft Critical Products & Services
Original
ML590PND ML703-1
Abstract: IL22 ) × DCR Temperature rise (t) = Winding power loss × 55.6°C t = (IL12 + IL22 ) × DCR × W 55.6°C W , 0.721 W 55.6°C = 40°C t = 0.721 W × W Example 2. MSD1260-153ML (IL1 = 2.4 A, IL2 = 1.3 A) Winding power loss = (2.4 2 + 1.3 2) × 0.085 = 0.633 W t = 0.633 W × 55.6°C = 35.2°C W Coupled Inductor Core and Coilcraft
Original
MSD1260
Abstract: Irms Winding power loss = (IL12 + IL22 ) × DCR Temperature rise (t) = Winding power loss × 55.6°C t = (IL12 + IL22 ) × DCR × W 55.6°C W Example 1. MSD1260-153ML (Equal current in each winding) Winding power loss = (2.06 2 + 2.06 2) × 0.085 = 0.721 W 55.6°C = 40°C t = 0.721 W × W Example 2. MSD1260-153ML (IL1 = 2.4 A, IL2 = 1.3 A) Winding power loss = (2.4 2 + 1.3 2) × 0.085 = 0.633 W t = 0.633 W × 55.6°C Coilcraft
Original
Abstract: IL22 ) × DCR in Watts (W) 55.6°C Temperature rise (t) = Winding power loss × W 55.6°C t = (IL12 + IL22 , 2.06 2) × 0.085 = 0.721 W 55.6°C = 40°C t = 0.721 W × W Example 2. MSD1260T-153ML (IL1 = 2.4 A, IL2 = 1.3 A) Winding power loss = (2.4 2 + 1.3 2) × 0.085 = 0.633 W t = 0.633 W × 55.6°C = 35.2°C W Coilcraft
Original
Abstract: Irms Winding power loss = (IL12 + IL22 ) × DCR Temperature rise (t) = Winding power loss × 55.6°C t = (IL12 + IL22 ) × DCR × W 55.6°C W Example 1. MSD1260-153ML (Equal current in each winding) Winding power loss = (2.06 2 + 2.06 2) × 0.085 = 0.721 W 55.6°C = 40°C t = 0.721 W × W Example 2. MSD1260-153ML (IL1 = 2.4 A, IL2 = 1.3 A) Winding power loss = (2.4 2 + 1.3 2) × 0.085 = 0.633 W t = 0.633 W × 55.6°C Coilcraft
Original
Abstract: IL22 ) × DCR in Watts (W) 55.6°C Temperature rise ( t) = Winding power loss × W 55.6°C t = (IL12 + , + 1.3 2) × 0.085 = 0.633 W t = 0.633 W × 55.6°C = 35.2°C W Specifications subject to change , ) Winding power loss = (2.06 2 + 2.06 2) × 0.085 = 0.721 W 55.6°C t = 0.721 W × = 40°C W Phone Coilcraft Critical Products & Services
Original
ML590PND472MLZ
Abstract: ) 55.6°C Temperature rise (t) = Winding power loss × W 55.6°C t = (IL12 + IL22 ) × DCR × W Example 1 , 55.6°C = 40°C t = 0.721 W × W Example 2. MSD1260T-153ML (IL1 = 2.4 A, IL2 = 1.3 A) Winding power loss = (2.4 2 + 1.3 2) × 0.085 = 0.633 W t = 0.633 W × 55.6°C = 35.2°C W Coupled Inductor Core and Winding Coilcraft
Original
Abstract: Winding power loss = (IL12 + IL22 ) × DCR Temperature rise (t) = Winding power loss × 55.6°C t = (IL12 + IL22 ) × DCR × W 55.6°C W Example 1. MSD1260-153ML (Equal current in each winding) Winding power loss = (2.06 2 + 2.06 2) × 0.085 = 0.721 W 55.6°C = 40°C t = 0.721 W × W Example 2. MSD1260-153ML (IL1 = 2.4 A, IL2 = 1.3 A) Winding power loss = (2.4 2 + 1.3 2) × 0.085 = 0.633 W t = 0.633 W × 55.6°C = Coilcraft
Original
Agilent 4284a
Abstract: Winding power loss = (IL12 + IL22 ) × DCR in Watts (W) 55.6°C Temperature rise (t) = Winding power loss × W 55.6°C t = (IL12 + IL22 ) × DCR × W Example 1. MSD1260T-153ML (Equal current in each winding) Winding power loss = (2.06 2 + 2.06 2) × 0.085 = 0.721 W 55.6°C = 40°C t = 0.721 W × W Example 2. MSD1260T-153ML (IL1 = 2.4 A, IL2 = 1.3 A) Winding power loss = (2.4 2 + 1.3 2) × 0.085 = 0.633 W t = 0.633 W × 55.6°C Coilcraft
Original
Abstract: Irms Winding power loss = (IL12 + IL22 ) × DCR Temperature rise (t) = Winding power loss × 55.6°C t = (IL12 + IL22 ) × DCR × W 55.6°C W Example 1. MSD1260-153ML (Equal current in each winding) Winding power loss = (2.06 2 + 2.06 2) × 0.085 = 0.721 W 55.6°C = 40°C t = 0.721 W × W Example 2. MSD1260-153ML (IL1 = 2.4 A, IL2 = 1.3 A) Winding power loss = (2.4 2 + 1.3 2) × 0.085 = 0.633 W t = 0.633 W × 55.6°C Coilcraft
Original
Abstract: ) 55.6°C Temperature rise (t) = Winding power loss × W 55.6°C t = (IL12 + IL22 ) × DCR × W Example 1 , 55.6°C = 40°C t = 0.721 W × W Example 2. MSD1260T-153ML (IL1 = 2.4 A, IL2 = 1.3 A) Winding power loss = (2.4 2 + 1.3 2) × 0.085 = 0.633 W t = 0.633 W × 55.6°C = 35.2°C W Coupled Inductor Core and Winding Coilcraft
Original
Abstract: . Winding power loss = (IL12 + IL22 ) × DCR Temperature rise (t) = Winding power loss × 55.6°C t = (IL12 , = (2.06 2 + 2.06 2) × 0.085 = 0.721 W 55.6°C = 40°C t = 0.721 W × W Example 2. MSD1260 , 55.6°C = 35.2°C W Coupled Inductor Core and Winding Loss Calculator This web-based utility allows , . 2010 55.6°C W Document 528-2 Revised 12/05/08 Document 528-3 Coupled Inductors for Coilcraft
Original
MSD1260-153 equal inductors MSD1260-472ML
Abstract: IL22 ) × DCR in Watts (W) 55.6°C Temperature rise ( t) = Winding power loss × W 55.6°C t = (IL12 + , + 1.3 2) × 0.085 = 0.633 W t = 0.633 W × 55.6°C = 35.2°C W Specifications subject to change , ) Winding power loss = (2.06 2 + 2.06 2) × 0.085 = 0.721 W 55.6°C t = 0.721 W × = 40°C W Phone Coilcraft Critical Products & Services
Original
MS590PND MS590PND824KSZ MS703-1
Abstract: rder N um ber LM 556CM See NS Package Num ber M14A O rd e r Num ber LM 556CN See NS Package Num ber , te 1) LM 556J, LM 556C J LM 556C N O p e ra tin g T e m p e ra tu re R a n g e s LM 556C LM 556 0 , LM 556C Min 4.5 3 10 Units Max 16 6 14 V mA mA Typ S u p p ly V o lta g e S u p p ly C u , rw is e s p e c ifie d ) (C o n tin u e d ) C onditions Min LM556 Typ Max Min LM 556C Typ M -
OCR Scan
U1 LM 555 LM 555 National LM 555 timer LM556/LM556C TL/H/7B52-3
Abstract: Irms Winding power loss = (IL12 + IL22 ) × DCR Temperature rise (t) = Winding power loss × 55.6°C t = (IL12 + IL22 ) × DCR × W 55.6°C W Example 1. MSD1260-153ML (Equal current in each winding) Winding power loss = (2.06 2 + 2.06 2) × 0.085 = 0.721 W 55.6°C = 40°C t = 0.721 W × W Example 2. MSD1260-153ML (IL1 = 2.4 A, IL2 = 1.3 A) Winding power loss = (2.4 2 + 1.3 2) × 0.085 = 0.633 W t = 0.633 W × 55.6°C Coilcraft
Original
473 coilcraft d
Abstract: ) 55.6°C Temperature rise (t) = Winding power loss × W 55.6°C t = (IL12 + IL22 ) × DCR × W Example 1 , 55.6°C = 40°C t = 0.721 W × W Example 2. MSD1260T-153ML (IL1 = 2.4 A, IL2 = 1.3 A) Winding power loss = (2.4 2 + 1.3 2) × 0.085 = 0.633 W t = 0.633 W × 55.6°C = 35.2°C W Coupled Inductor Core and Winding Coilcraft
Original
Abstract: rise (t) = Winding power loss × 55.6°C t = (IL12 + IL22 ) × DCR × W 55.6°C W Example 1. MSD1260-153ML (Equal current in each winding) Winding power loss = (2.06 2 + 2.06 2) × 0.085 = 0.721 W 55.6°C = 40°C t , 2) × 0.085 = 0.633 W t = 0.633 W × 55.6°C = 35.2°C W Coupled Inductor Core and Winding Loss Coilcraft
Original
4284ALCR transformer mtbf
Abstract: ) 55.6°C Temperature rise (t) = Winding power loss × W 55.6°C t = (IL12 + IL22 ) × DCR × W Example 1 , 55.6°C = 40°C t = 0.721 W × W Example 2. MSD1260T-153ML (IL1 = 2.4 A, IL2 = 1.3 A) Winding power loss = (2.4 2 + 1.3 2) × 0.085 = 0.633 W t = 0.633 W × 55.6°C = 35.2°C W Coupled Inductor Core and Winding Coilcraft
Original
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