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-556C Datasheet

Part Manufacturer Description PDF Type
556C1 Test Products International Equipment - Environmental Testers, Test and Measurement, DGTL AIR VELOCITY/AIR FLOW METER Original

-556C

Catalog Datasheet MFG & Type PDF Document Tags
Abstract: : Winding power loss = (IL12 + IL22 ) × DCR in Watts (W) 55.6°C Temperature rise (t) = Winding power loss × W 55.6°C t = (IL12 + IL22 ) × DCR × W Example 1. MSD1260T-153ML (Equal current in each winding) Winding power loss = (2.06 2 + 2.06 2) × 0.085 = 0.721 W 55.6°C = 40°C t = 0.721 W × W Example 2. MSD1260T-153ML (IL1 = 2.4 A, IL2 = 1.3 A) Winding power loss = (2.4 2 + 1.3 2) × 0.085 = 0.633 W t = 0.633 W × 55.6°C Coilcraft
Original
MSD1260T

MSD1260T-224KL

Abstract: SR-332 power loss = (IL12 + IL22 ) × DCR in Watts (W) 55.6°C Temperature rise (t) = Winding power loss × W 55.6°C t = (IL12 + IL22 ) × DCR × W Example 1. MSD1260T-153ML (Equal current in each winding) Winding power loss = (2.06 2 + 2.06 2) × 0.085 = 0.721 W 55.6°C = 40°C t = 0.721 W × W Example 2 , 0.633 W × 55.6°C = 35.2°C W Coupled Inductor Core and Winding Loss Calculator This web-based
Coilcraft
Original
MSD1260T-224KL SR-332 556C
Abstract: Winding power loss = (IL12 + IL22 ) × DCR in Watts (W) 55.6°C Temperature rise ( t) = Winding power loss × W 55.6°C t = (IL12 + IL22 ) × DCR × W Example 1. 590PND153 (Equal current in each winding) Winding power loss = (2.06 2 + 2.06 2) × 0.085 = 0.721 W 55.6°C t = 0.721 W × = 40°C W Example 2. 590PND153 (I L1 = 2.4 A, IL2 = 1.3 A) Winding power loss = (2.4 2 + 1.3 2) × 0.085 = 0.633 W t = 0.633 W × 55.6°C Coilcraft Critical Products & Services
Original
ML590PND ML703-1
Abstract: IL22 ) × DCR Temperature rise (t) = Winding power loss × 55.6°C t = (IL12 + IL22 ) × DCR × W 55.6°C W , 0.721 W 55.6°C = 40°C t = 0.721 W × W Example 2. MSD1260-153ML (IL1 = 2.4 A, IL2 = 1.3 A) Winding power loss = (2.4 2 + 1.3 2) × 0.085 = 0.633 W t = 0.633 W × 55.6°C = 35.2°C W Coupled Inductor Core and Coilcraft
Original
MSD1260
Abstract: Irms Winding power loss = (IL12 + IL22 ) × DCR Temperature rise (t) = Winding power loss × 55.6°C t = (IL12 + IL22 ) × DCR × W 55.6°C W Example 1. MSD1260-153ML (Equal current in each winding) Winding power loss = (2.06 2 + 2.06 2) × 0.085 = 0.721 W 55.6°C = 40°C t = 0.721 W × W Example 2. MSD1260-153ML (IL1 = 2.4 A, IL2 = 1.3 A) Winding power loss = (2.4 2 + 1.3 2) × 0.085 = 0.633 W t = 0.633 W × 55.6°C Coilcraft
Original
Abstract: IL22 ) × DCR in Watts (W) 55.6°C Temperature rise (t) = Winding power loss × W 55.6°C t = (IL12 + IL22 , 2.06 2) × 0.085 = 0.721 W 55.6°C = 40°C t = 0.721 W × W Example 2. MSD1260T-153ML (IL1 = 2.4 A, IL2 = 1.3 A) Winding power loss = (2.4 2 + 1.3 2) × 0.085 = 0.633 W t = 0.633 W × 55.6°C = 35.2°C W Coilcraft
Original
Abstract: Irms Winding power loss = (IL12 + IL22 ) × DCR Temperature rise (t) = Winding power loss × 55.6°C t = (IL12 + IL22 ) × DCR × W 55.6°C W Example 1. MSD1260-153ML (Equal current in each winding) Winding power loss = (2.06 2 + 2.06 2) × 0.085 = 0.721 W 55.6°C = 40°C t = 0.721 W × W Example 2. MSD1260-153ML (IL1 = 2.4 A, IL2 = 1.3 A) Winding power loss = (2.4 2 + 1.3 2) × 0.085 = 0.633 W t = 0.633 W × 55.6°C Coilcraft
Original
Abstract: ) 55.6°C Temperature rise (t) = Winding power loss × W 55.6°C t = (IL12 + IL22 ) × DCR × W Example 1 , 55.6°C = 40°C t = 0.721 W × W Example 2. MSD1260T-153ML (IL1 = 2.4 A, IL2 = 1.3 A) Winding power loss = (2.4 2 + 1.3 2) × 0.085 = 0.633 W t = 0.633 W × 55.6°C = 35.2°C W Coupled Inductor Core and Winding Coilcraft
Original

Agilent 4284a

Abstract: Winding power loss = (IL12 + IL22 ) × DCR Temperature rise (t) = Winding power loss × 55.6°C t = (IL12 + IL22 ) × DCR × W 55.6°C W Example 1. MSD1260-153ML (Equal current in each winding) Winding power loss = (2.06 2 + 2.06 2) × 0.085 = 0.721 W 55.6°C = 40°C t = 0.721 W × W Example 2. MSD1260-153ML (IL1 = 2.4 A, IL2 = 1.3 A) Winding power loss = (2.4 2 + 1.3 2) × 0.085 = 0.633 W t = 0.633 W × 55.6°C =
Coilcraft
Original
Agilent 4284a

ML590PND472MLZ

Abstract: ML590PND IL22 ) × DCR in Watts (W) 55.6°C Temperature rise ( t) = Winding power loss × W 55.6°C t = (IL12 + , + 1.3 2) × 0.085 = 0.633 W t = 0.633 W × 55.6°C = 35.2°C W Specifications subject to change , ) Winding power loss = (2.06 2 + 2.06 2) × 0.085 = 0.721 W 55.6°C t = 0.721 W × = 40°C W Phone
Coilcraft Critical Products & Services
Original
ML590PND472MLZ
Abstract: Winding power loss = (IL12 + IL22 ) × DCR in Watts (W) 55.6°C Temperature rise (t) = Winding power loss × W 55.6°C t = (IL12 + IL22 ) × DCR × W Example 1. MSD1260T-153ML (Equal current in each winding) Winding power loss = (2.06 2 + 2.06 2) × 0.085 = 0.721 W 55.6°C = 40°C t = 0.721 W × W Example 2. MSD1260T-153ML (IL1 = 2.4 A, IL2 = 1.3 A) Winding power loss = (2.4 2 + 1.3 2) × 0.085 = 0.633 W t = 0.633 W × 55.6°C Coilcraft
Original
Abstract: Irms Winding power loss = (IL12 + IL22 ) × DCR Temperature rise (t) = Winding power loss × 55.6°C t = (IL12 + IL22 ) × DCR × W 55.6°C W Example 1. MSD1260-153ML (Equal current in each winding) Winding power loss = (2.06 2 + 2.06 2) × 0.085 = 0.721 W 55.6°C = 40°C t = 0.721 W × W Example 2. MSD1260-153ML (IL1 = 2.4 A, IL2 = 1.3 A) Winding power loss = (2.4 2 + 1.3 2) × 0.085 = 0.633 W t = 0.633 W × 55.6°C Coilcraft
Original
Abstract: ) 55.6°C Temperature rise (t) = Winding power loss × W 55.6°C t = (IL12 + IL22 ) × DCR × W Example 1 , 55.6°C = 40°C t = 0.721 W × W Example 2. MSD1260T-153ML (IL1 = 2.4 A, IL2 = 1.3 A) Winding power loss = (2.4 2 + 1.3 2) × 0.085 = 0.633 W t = 0.633 W × 55.6°C = 35.2°C W Coupled Inductor Core and Winding Coilcraft
Original

MSD1260-153

Abstract: MSD1260-472ML . Winding power loss = (IL12 + IL22 ) × DCR Temperature rise (t) = Winding power loss × 55.6°C t = (IL12 , = (2.06 2 + 2.06 2) × 0.085 = 0.721 W 55.6°C = 40°C t = 0.721 W × W Example 2. MSD1260 , 55.6°C = 35.2°C W Coupled Inductor Core and Winding Loss Calculator This web-based utility allows , . 2010 55.6°C W Document 528-2 Revised 12/05/08 Document 528-3 Coupled Inductors for
Coilcraft
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MSD1260-153 MSD1260-472ML equal inductors

MS590PND824KSZ

Abstract: MS590PND IL22 ) × DCR in Watts (W) 55.6°C Temperature rise ( t) = Winding power loss × W 55.6°C t = (IL12 + , + 1.3 2) × 0.085 = 0.633 W t = 0.633 W × 55.6°C = 35.2°C W Specifications subject to change , ) Winding power loss = (2.06 2 + 2.06 2) × 0.085 = 0.721 W 55.6°C t = 0.721 W × = 40°C W Phone
Coilcraft Critical Products & Services
Original
MS590PND MS590PND824KSZ MS703-1

U1 LM 555

Abstract: 556CN rder N um ber LM 556CM See NS Package Num ber M14A O rd e r Num ber LM 556CN See NS Package Num ber , te 1) LM 556J, LM 556C J LM 556C N O p e ra tin g T e m p e ra tu re R a n g e s LM 556C LM 556 0 , LM 556C Min 4.5 3 10 Units Max 16 6 14 V mA mA Typ S u p p ly V o lta g e S u p p ly C u , rw is e s p e c ifie d ) (C o n tin u e d ) C onditions Min LM556 Typ Max Min LM 556C Typ M
-
OCR Scan
U1 LM 555 LM 555 National LM 555 timer LM556/LM556C TL/H/7B52-3

MSD1260-153

Abstract: 473 coilcraft d Irms Winding power loss = (IL12 + IL22 ) × DCR Temperature rise (t) = Winding power loss × 55.6°C t = (IL12 + IL22 ) × DCR × W 55.6°C W Example 1. MSD1260-153ML (Equal current in each winding) Winding power loss = (2.06 2 + 2.06 2) × 0.085 = 0.721 W 55.6°C = 40°C t = 0.721 W × W Example 2. MSD1260-153ML (IL1 = 2.4 A, IL2 = 1.3 A) Winding power loss = (2.4 2 + 1.3 2) × 0.085 = 0.633 W t = 0.633 W × 55.6°C
Coilcraft
Original
473 coilcraft d
Abstract: ) 55.6°C Temperature rise (t) = Winding power loss × W 55.6°C t = (IL12 + IL22 ) × DCR × W Example 1 , 55.6°C = 40°C t = 0.721 W × W Example 2. MSD1260T-153ML (IL1 = 2.4 A, IL2 = 1.3 A) Winding power loss = (2.4 2 + 1.3 2) × 0.085 = 0.633 W t = 0.633 W × 55.6°C = 35.2°C W Coupled Inductor Core and Winding Coilcraft
Original

transformer mtbf

Abstract: 4284ALCR rise (t) = Winding power loss × 55.6°C t = (IL12 + IL22 ) × DCR × W 55.6°C W Example 1. MSD1260-153ML (Equal current in each winding) Winding power loss = (2.06 2 + 2.06 2) × 0.085 = 0.721 W 55.6°C = 40°C t , 2) × 0.085 = 0.633 W t = 0.633 W × 55.6°C = 35.2°C W Coupled Inductor Core and Winding Loss
Coilcraft
Original
transformer mtbf 4284ALCR
Abstract: ) 55.6°C Temperature rise (t) = Winding power loss × W 55.6°C t = (IL12 + IL22 ) × DCR × W Example 1 , 55.6°C = 40°C t = 0.721 W × W Example 2. MSD1260T-153ML (IL1 = 2.4 A, IL2 = 1.3 A) Winding power loss = (2.4 2 + 1.3 2) × 0.085 = 0.633 W t = 0.633 W × 55.6°C = 35.2°C W Coupled Inductor Core and Winding Coilcraft
Original
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